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What was the starting speed if a car accelerating at ${3}{m/s^2}$ for ${4}{s}$ reaches a speed of ${28}{m/s}$?
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v=u + at

u= v-at

=28-(3)(4)

=28-12

= 16 m/s
by Wooden (2,549 points)
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Vi = ? Vf = 28 m/s a = 3 m/s^2 t = 4s Vf = Vi + at 28 = Vi + (3)(4) 28 = Vi + 12 28 - 12 = Vi Vi = 16 m/s
by Wooden (1,126 points)
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Sorry, im adding each solution on each line but when i save it comes out together, apologies
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Vi = Vf - at

= 28 - (3)(4)

= 28 - 12

= 16m/s
by Wooden (786 points)

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