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Solve the equation $3 x^{2}+3 x-4=0$, giving the answers correct to 3 significant figures.
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$\textbf{Answer:}$

$x_1 = 0.753 , \ x_2 = -1.76$

$\textbf{Explanation:}$

We are going to use the quadratic formula $x_1,x_2 = \frac{-b \pm \sqrt{b^2-4ac}}{2a}$ on $3x^2+3x-4=0$

where $a= 3, \ b = 3 ,\ c=-4$

$x_1, x_2 = \frac{-3 \pm \sqrt{3^2 -4(3)(-4)}}{2(3)}$

$x_1, x_2 = \frac{-3 \pm \sqrt{57}}{6}$

$x_1 = \frac{-3+ \sqrt{57}}{6}$ and $x_2 = \frac{-3- \sqrt{57}}{6}$

$x_1 = 0.752$ and $x_2 = -1.76$
by Wooden (1,832 points)

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