Sites: Global Q&A | Wits | MathsGee Club | Joburg Libraries | StartUps | Zimbabwe | OER

MathsGee is Zero-Rated (You do not need data to access) on: Telkom |Dimension Data | Rain | MWEB

0 like 0 dislike
33 views
An airfreight company has various classes of freight. In one of these classes the average weight of packages is $10 \mathrm{~kg}$ and the variance of the weight distribution is $9 \mathrm{~kg}^{2}$. Assuming that the package weights are independent (it is not the case that a single company is sending a large number of identical packages, for instance), estimate the probability that 100 packages will have total weight more than $1020 \mathrm{~kg}$.
| 33 views

0 like 0 dislike
The central limit theorem says $\sum W_{i}$ is approximately $N\left(1,000,30^{2}\right)$ so that $P\left(\sum W_{i}>1,020\right) \approx$ $P[Z>(1,020-1,000) / 30=0.67]=0.251$
by Diamond (88,180 points)

0 like 0 dislike
0 like 0 dislike
0 like 0 dislike
1 like 0 dislike
0 like 0 dislike
1 like 0 dislike
0 like 0 dislike
1 like 0 dislike
0 like 0 dislike
1 like 0 dislike
0 like 0 dislike
0 like 0 dislike
0 like 0 dislike
0 like 0 dislike
0 like 0 dislike
0 like 0 dislike
0 like 0 dislike
0 like 0 dislike
0 like 0 dislike
0 like 0 dislike
1 like 0 dislike
0 like 0 dislike
0 like 0 dislike
0 like 0 dislike
0 like 0 dislike
0 like 0 dislike
0 like 0 dislike
1 like 0 dislike
0 like 0 dislike
0 like 0 dislike
0 like 0 dislike
0 like 0 dislike
0 like 0 dislike
0 like 0 dislike