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A bag contains 2 red, 3 green and 2 blue balls. Two balls are drawn at random. What is the probability that none of the balls drawn is blue?
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Using the multiplication rule:

P(none of the balls drawn is blue) = P(first ball not blue and second ball not blue) = P(first ball not blue) x P(second ball not blue)

= (5/7) x (4/6)

= (20/42) = 10/21

by Diamond (43,254 points)

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