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What is the probability of getting a sum 9 from two throws of a dice?
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$11\%$

Explanation:

Possible outcomes of two dice $= 6 \times 6 = 36$ Outcomes

To get $9$, the dice must be either $(5,4), (4,5), (3,6),$ or $(6,3)$ therefore $4$ possible combinations.

Probability of total $9 = \dfrac{4}{36} = \dfrac{1}{9} = 0.11 = 11\%$

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