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Solve the simultaneous equations $a+b=4$ and $2 a+b=6$
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$\textbf{Answer:}$

$a = 2, \ b=2$

$\textbf{Explaination:}$

$a+b=4$

$\implies a= 4-b$   . . .(1)

and $2a+b=6$ . . (2)

substitube (1) into (2) we get,

$2(4-b)+b=6$

$8-2b+b=6$

$-b= -2$

$b=2$ . . .(3)

substitute (3) into (1)

$a=4-2$

$a=2$
by Wooden (2,882 points)

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