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$\dfrac{x-2}{ 4} - \dfrac{3 x+5}{ 7}= -3, x=?$
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There are two fractions containing $x$ and the denominators are different. First, let us find a common denominator to simplify the expression. The least common multiplier of 4 and 7 is 28 . Then,

$7(x-2) / 28-4(3 x+5) / 28=-3 \cdot 28 / 28 \ldots$ Since both sides are written on the denominator 28 now, we can eliminate them:

$7(x-2)-4(3 x+5)=-84$
$7 x-14-12 x-20=-84$
$-5 x=-84+14+20$
$-5 x=-50$
$x=50 / 5$
$x=10$
ago by Diamond (78,880 points)

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