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Solve the quadratic equation $3x^2-10x+3=0$
ago in Mathematics by Diamond (78,880 points) | 4 views

1 Answer

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&3 x^{2}-10 x+3=0 \\
&x_{12}=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a} \\
&x_{12}=\frac{-(-10) \pm \sqrt{(-10)^{2}-4 \cdot 3 \cdot 3}}{2 \cdot 3} \\
&x_{12}=\frac{10 \pm \sqrt{100-36}}{6} \\
&x_{12}=\frac{10 \pm \sqrt{64}}{6} \\
&x_{12}=\frac{10 \pm 8}{6} \\
&x_{1}=\frac{10+8}{6}=\frac{18}{6}=3 \\
ago by Diamond (78,880 points)

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