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Using the factoring method, solve the quadratic equation: $x^{2}+4 x+4=0$
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$x^{2} +4 x+4=0 \ldots$ We try to separate the middle term $4 x$ to find common factors with $x^{2}$ and 4 separately:
$x^{2} +2 x+2 x+4=0 \ldots$ Here, we see that $x$ is a common factor for $x^{2}$ and $2 x_{1}$ and 2 is a common factor for $2 x$ and 4 :
$x(x+2)+2(x+2)=0 \ldots$ Here, we have $x$ times $x+2$ and
2 times $x+2$ summed up. This means that we have $x+2$
times $x+2$
$(x+2)(x+2)=0$
$(x+2) =0 \ldots$ This is true if only if $x+2$ is equal to zero.
$x+2=0$
$x=-2$
by Diamond (80,744 points)

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