$2 \mathrm{x}^{2}-3 \mathrm{x}=0 \ldots$ we see that both of the terms contain $\mathrm{x}$; so we can take it out as a factor:

$x(2 x-3)=0 \ldots$ two terms are multiplied and the result is zero. This means that either of the terms or both of the

terms can be equal to zero:

$\mathrm{x}=0 \ldots$ this is one solution

$2 x-3=0$

$2 x=3$

$x=3 / 2$

$x=1.5 \ldots$ this is the second solution.

So, the solutions are 0 and $1.5 .$