Quality Learning Support For Better Outcomes
First time here? Checkout the FAQs!
MathsGee is Zero-Rated (You do not need data to access) on: Telkom |Dimension Data | Rain | MWEB

0 like 0 dislike
Using the quadratic formula, solve the quadratic equation: $x^{2}-9 x+14=0$
ago in Mathematics by Diamond (78,880 points) | 5 views

1 Answer

0 like 0 dislike
Best answer
To solve the equation, we need the equation in the form $a x^{2}+b x+c=0$. $x^{2}-9 x+14=0$ is already in this form.
The quadratic formula to find the roots of a quadratic equation is:
$\mathrm{x}_{1,2}=(-\mathrm{b} \pm \sqrt{\Delta}) / 2 \mathrm{a}$ where $\Delta=\mathrm{b}^{2}-4 \mathrm{ac}$ and is called the discriminant of the quadratic equation.
In our question, the equation is $x^{2}-9 x+14=0$. By remembering the form $a x^{2}+b x+c=0$ :
$\mathrm{a}=1, \mathrm{~b}=-9, \mathrm{c}=14$
So, we can find the discriminant first, and then the roots of the equation:
$\Delta=b^{2}-4 a c=(-9)^{2}-4 * 1 * 14=81-56=25$
$x_{1,2}=(-b \pm \sqrt{\Delta}) / 2 a=(-(-9) \pm \sqrt{25}) / 2=(9 \pm 5) / 2$
This means that the roots are, $x_{1}=(9-5) / 2=2$ and $x^{2}=(9+5) / 2=7$
ago by Diamond (78,880 points)

Related questions

Join the MathsGee community and get study support for success - MathsGee provides answers to subject-specific educational questions for improved outcomes.

On MathsGee Answers, you can:

1. Ask questions
2. Answer questions
3. Comment on Answers
4. Vote on Questions and Answers
5. Donate to your favourite users

Enter your email address:

MathsGee Tools

Math Worksheet Generator

Math Algebra Solver

Trigonometry Simulations

Vectors Simulations

Matrix Arithmetic Simulations

Matrix Transformations Simulations

Quadratic Equations Simulations

Probability & Statistics Simulations

PHET Simulations

Visual Statistics

MathsGee ZOOM | eBook