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The height (in metres) of a golf ball that is hit into the air after $t$ seconds, is given by $h(t)= 20t-5t^2$.  Determine the average velocity of the ball during the first two seconds
in Grade 12 Maths by Wooden (2k points) | 35 views

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h(t)= 20t- 5t^2

h(2)= 20(2)- 5(2)^2= 20m

h(0)= 0m

for t let h(t)= 0

0= 20t- 5t^2

0= 5t(4-t)

5t= 0s      t= 4 s

V= change in displacement/ change in time

= 30- 0/ 4-0

=30/4

= 7.5 m/s

 

 

by Wooden (2.3k points)
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