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Given: $f(x)=2x^2-x$

1. Use the definition of the derivative to calculate $f'(x)$.
2. Hence, calculate the co-ordinates of the point at which the gradient of the tangent to the graph of $f$ is $7$.
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1. dy/dx = 4x -1 which is gradient

2. 4x-1=7

x= 2

y= 2(2)^2 - 2 =6

(2;6) point
by Silver Status (31.3k points)