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$$4x + y = 1 \\ 2x + 2y = -4$$

In this system of equations above, what is the value of x?

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4x + y = 1                    (i)

2x + 2y = -4                (ii)

Multiplying (i) by 2 gives: 8x + 2y = 2                (iii)

(iii) - (ii) gives 6x = 2 - (-4) = 6

This implies that x = 1

Substituting 6 for x in (i) gives: (4)(1) + y = 1

y = 1 - 4 = -3

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