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If $a = 1 + \frac{1}{4} +\frac{1}{16} + \frac{1}{64}$ and $b = 1 + \frac{1}{4}a$, then what is the value of $a - b$?
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a = { (1) + (1/4) + (1/16) + (1/32) }

a = 43/32

b = 1 + (1/4)a.... Substitute value of a

b = 1 + (1/4)x(43/32)

b = 171/128

The value of a - b

(43/32) - (171/128) = 1/128

by Wooden (796 points)

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