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Two cars, A and B, are moving at speeds of 15 m·s-1 and 30 m·s-1 in the same direction. They are side by side when both drivers observe an obstruction ahead of them. Both drivers apply their brakes and accelerate at –4,5 m·s-2 until both cars come to rest. Ignore the reaction time of the drivers.

1. Calculate the: a. Time it takes car A to come to rest
                           b. Stopping distance of car A

2. Which car (A or B) has the longer stopping distance? Support the answer with a calculation.

3. What conclusion can be made about the relationship between speed and stopping distance?
in Grade 10 Physical Sciences by Silver Status (31.3k points)
edited by | 10 views

1 Answer

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1. a. vf =vi + aΔt
          0 = 15 + (-4,5)Δt
           Δt = 3,33 s

     b. vf^2 = vi^2 + 2aΔx
             0^2 = 15^2 + 2(-4,5)Δx
              Δx = 25 m

2. vf^2 = vi^2 + 2aΔx
     0^2 = 30^2 + 2(-4,5)Δx
        Δx = 100 m
Car B therefore has a larger stopping distance as100 m > 25 m.

3. The greater the speed, the greater the stopping distance if acceleration is constant.
by Silver Status (31.3k points)
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