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What is the largest integer n such that $\frac{1}{2^{n}} > 0.01$?
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(1/(2^n)) > 0.01

Multiplying and dividing both sides by (1/(2^n)) and 0.01 gives 100 > (2^n)

log 100 > log (2^n) = n log 2

((log 100)/(log2)) > n

6.643.. > n

Therefore 6 is the largest integer n such that (1/(2^n)) > 0.01
by Diamond (40,740 points)
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