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$x ; 4 ; y$ form an arithmetic sequence while $x ; \sqrt{15} ; y$ form a geometric sequence. Calculate $x$ and $y$.
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common difference,

4-x=y-4

x= 8-y

common ratio,

sqroot(15)/x = y/sqroot(15)

15/x =y

hence y= 15/(8-y)

y(8-y) = 15

y^2 -8y +15=0

(y-3)(y-5)=0

y= 3 or y=5

Then x=15/3 or x= 15/5= 3
by Diamond (44,680 points)

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