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How do i factorise $8m^{6} + n^{9}$ ?
in Mathematics by Diamond (53,824 points) | 26 views

1 Answer

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apply laws of exponents to make exponents of 3

= (2m^2)^3 + (n^3)^3, this is now sum of 2 cubes

= (2m^2 + n^3)(4m^4 -2m^2.n^3 + n^6)
by Diamond (40,306 points)

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