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58 views
Simplify $\dfrac{p^3 + q^3}{p^2} \times \dfrac{3p-3q}{p^2-q^2}$
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factorize sum of 2 cubes and difference of 2 squares, then do cross multiplication

(p+q)(p^2 -pq+q^2)/p^2  x  3(p-q)/(p-q)(p+q)

= (3p^2 - 3pq+3q^2)/p^2
by Diamond (44,766 points)

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