Quality Learning Support For Better Outcomes
First time here? Checkout the FAQs!
x
MathsGee is Zero-Rated (You do not need data to access) on: Telkom |Dimension Data | Rain | MWEB

0 like 0 dislike
100 views

The general term of the sequence is given by $T_{n} = an^{2} + bn + c$

$$T_{2} - T_{1} = 4 $$

$$T_{3} - T_{2} = 6 $$

$$T_{4} - T_{3} = 8 $$

 $$ T_{2} = 6$$

  • Calculate a,b and c
  • Determine the 12th term of the sequence. 
in Mathematics by Diamond (78,454 points) | 100 views

1 Answer

0 like 0 dislike
T3 - 6=6

T3=12

then T2-T1=4

         6-T1=4

                T1=2

T4-T3=8

T4-12=8

      T4=20

Therefore terms= 2,6,12,20

1st difference=       4,6,8

2nd difference=        2,2,....

2a=2

 a=1

3a+b=4

3(1) + b=4

   b= 1

a+b+c= 2

c= 2-1- 1= 0

giving Tn= n^2 + n

T12 = 12^2 + 12 = 156
by Diamond (44,036 points)

Related questions

Join the MathsGee community and get study support for success - MathsGee provides answers to subject-specific educational questions for improved outcomes.



On MathsGee Answers, you can:


1. Ask questions
2. Answer questions
3. Comment on Answers
4. Vote on Questions and Answers
5. Donate to your favourite users

Enter your email address:

MathsGee Tools

Math Worksheet Generator

Math Algebra Solver

Trigonometry Simulations

Vectors Simulations

Matrix Arithmetic Simulations

Matrix Transformations Simulations

Quadratic Equations Simulations

Probability & Statistics Simulations

PHET Simulations

Visual Statistics

MathsGee ZOOM | eBook