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Simplify $\dfrac{1}{m+n} + \dfrac{3mn}{m^{3} + n^{3}}$
in Grade 10 Maths by Diamond (50,571 points) | 24 views

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factorize sum of two cubes on the denominator to get LCD

$\frac{1}{(m+n)}   +     \frac{3mn}{[(m+n)(m^2 -mn +n^2)]}$

$=\frac{[m^2 -mn+n^2 +3m^2n+3mn^2]}{[(m+n)((m)^2 -mn+n^2)]}$
by Diamond (39,577 points)

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