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Simplify $\dfrac{1}{m+n} + \dfrac{3mn}{m^{3} + n^{3}}$
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$\frac{1}{(m+n)} + \frac{3mn}{[(m+n)(m^2 -mn +n^2)]}$
$=\frac{[m^2 -mn+n^2 +3m^2n+3mn^2]}{[(m+n)((m)^2 -mn+n^2)]}$